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-24x+24x^2=24
We move all terms to the left:
-24x+24x^2-(24)=0
a = 24; b = -24; c = -24;
Δ = b2-4ac
Δ = -242-4·24·(-24)
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24\sqrt{5}}{2*24}=\frac{24-24\sqrt{5}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24\sqrt{5}}{2*24}=\frac{24+24\sqrt{5}}{48} $
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